刚刚看到一道数学题的解法 有几步看不懂 已知一次函数y=mx+n与反比例函数y=(3n-m)/x的图像相交于点(1/2,2),求m,n的值及另一个交点.Y=MX+N过(1/2,2)----> 2=M/2+NY=(3N-M)/X过(1/2,2)----> 2=(3N-M)/(1/2)=2(
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![刚刚看到一道数学题的解法 有几步看不懂 已知一次函数y=mx+n与反比例函数y=(3n-m)/x的图像相交于点(1/2,2),求m,n的值及另一个交点.Y=MX+N过(1/2,2)----> 2=M/2+NY=(3N-M)/X过(1/2,2)----> 2=(3N-M)/(1/2)=2(](/uploads/image/z/3726548-44-8.jpg?t=%E5%88%9A%E5%88%9A%E7%9C%8B%E5%88%B0%E4%B8%80%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%E7%9A%84%E8%A7%A3%E6%B3%95+%E6%9C%89%E5%87%A0%E6%AD%A5%E7%9C%8B%E4%B8%8D%E6%87%82+%E5%B7%B2%E7%9F%A5%E4%B8%80%E6%AC%A1%E5%87%BD%E6%95%B0y%3Dmx%2Bn%E4%B8%8E%E5%8F%8D%E6%AF%94%E4%BE%8B%E5%87%BD%E6%95%B0y%3D%EF%BC%883n-m%EF%BC%89%2Fx%E7%9A%84%E5%9B%BE%E5%83%8F%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9%EF%BC%881%2F2%2C2%EF%BC%89%2C%E6%B1%82m%2Cn%E7%9A%84%E5%80%BC%E5%8F%8A%E5%8F%A6%E4%B8%80%E4%B8%AA%E4%BA%A4%E7%82%B9.Y%3DMX%2BN%E8%BF%87%281%2F2%2C2%29----%3E+2%3DM%2F2%2BNY%3D%283N%EF%BC%8DM%29%2FX%E8%BF%87%281%2F2%2C2%29----%3E+2%3D%283N-M%29%2F%281%2F2%29%3D2%28)
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