集合 答案看不懂...设y=x^2+bx+c(b,c∈R),且A={xIx=x^2+bx+c},B={xIx=(x^2+bx+c)^2+b(x^2+bx+c)+c},证明,如果A为只含1个元素的集合,则A=B设A={a},则关于x的方程x^2+bx+c-x=0有两个相等的实根a,于是x^2+bx+c-x=(x-a)^2,x^2+bx+
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![集合 答案看不懂...设y=x^2+bx+c(b,c∈R),且A={xIx=x^2+bx+c},B={xIx=(x^2+bx+c)^2+b(x^2+bx+c)+c},证明,如果A为只含1个元素的集合,则A=B设A={a},则关于x的方程x^2+bx+c-x=0有两个相等的实根a,于是x^2+bx+c-x=(x-a)^2,x^2+bx+](/uploads/image/z/3726876-12-6.jpg?t=%E9%9B%86%E5%90%88+%E7%AD%94%E6%A1%88%E7%9C%8B%E4%B8%8D%E6%87%82...%E8%AE%BEy%3Dx%5E2%2Bbx%2Bc%28b%2Cc%E2%88%88R%29%2C%E4%B8%94A%3D%7BxIx%3Dx%5E2%2Bbx%2Bc%7D%2CB%3D%7BxIx%3D%28x%5E2%2Bbx%2Bc%29%5E2%2Bb%28x%5E2%2Bbx%2Bc%29%2Bc%7D%2C%E8%AF%81%E6%98%8E%2C%E5%A6%82%E6%9E%9CA%E4%B8%BA%E5%8F%AA%E5%90%AB1%E4%B8%AA%E5%85%83%E7%B4%A0%E7%9A%84%E9%9B%86%E5%90%88%2C%E5%88%99A%3DB%E8%AE%BEA%3D%7Ba%7D%2C%E5%88%99%E5%85%B3%E4%BA%8Ex%E7%9A%84%E6%96%B9%E7%A8%8Bx%5E2%2Bbx%2Bc-x%3D0%E6%9C%89%E4%B8%A4%E4%B8%AA%E7%9B%B8%E7%AD%89%E7%9A%84%E5%AE%9E%E6%A0%B9a%2C%E4%BA%8E%E6%98%AFx%5E2%2Bbx%2Bc-x%3D%28x-a%29%5E2%2Cx%5E2%2Bbx%2B)
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