http://zhidao.baidu.com/question/409239811.html?quesup2&oldq=1 这有道题

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http://zhidao.baidu.com/question/409239811.html?quesup2&oldq=1 这有道题
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http://zhidao.baidu.com/question/409239811.html?quesup2&oldq=1 这有道题
http://zhidao.baidu.com/question/409239811.html?quesup2&oldq=1 这有道题

http://zhidao.baidu.com/question/409239811.html?quesup2&oldq=1 这有道题
=[cos(π/4+α)]^2+[cos(π/2-(π/4+α))]^2
=[cos(π/4+α)]^2+[sin(π/4+α)]^2
=1