y+2z=-2;3x+y-4z=1;2x-y+2z=8
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y+2z=-2;3x+y-4z=1;2x-y+2z=8
y+2z=-2;3x+y-4z=1;2x-y+2z=8
y+2z=-2;3x+y-4z=1;2x-y+2z=8
y+2z=-2 (1)
3x+y-4z=1 (2)
2x-y+2z=8 (3)
(1)+(3)
2x+4z=6
x+2z=3 (4)
(2)+(3)
5x-2z=9 (5)
(4)+(5)
6x=12
x=2
z=(3-x)/2=1/2
y=2x+2z-8=-3
y+2z=-2 (1)
3x-4z=1 (2)
2x-y=8 (3)
(1)+(3)
2x+2z=6
所以4x+4z=12 (4)
(2)+(4)
7x=13
x=13/7
y=2x-8=-30/7
z=(-y-2)/2=8/7
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
x+y+z=6 x+2y+3z=14 y+1=z
2x+z=10 x+y-z=4 3x-y-z=0
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值
x+y+z=2 4x+2y+z=4 2x+3y+z=1
4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1
3x-y+2z=-1 4x+y+z=5 x-2y-z=-2
x-y-z=1 2x+y-3z=4 3x-2y-z=-1
x+y-z=6 x-3y+2z=1 3x+2y-z=4 阿
x+y-z=6,x-3y+2z=1,3x+2y-z=4
x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快
3x+2y+z=4 x+y+z=10 2x+3y-z=1