1又1/3+7/12-9/20+11/30-13/42=多少?
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1又1/3+7/12-9/20+11/30-13/42=多少?
1又1/3+7/12-9/20+11/30-13/42=多少?
1又1/3+7/12-9/20+11/30-13/42=多少?
=4/3+(1/3+1/4)-(1/4+1/5)+(1/5+1/6)-(1/6+1/7)
=4/3+1/3+1/4-1/4-1/5+1/5+1/6-1/6-1/7
=5/3-1/7
=32/21
=1又21分11
32/21
1又1/3+7/12-9/20+11/30-13/42
=1+1/3+1/3+1/4-(1/4+1/5)+(1/5+1/6)-(1/6-1/7)
=1+1/3+1/3+1/4-1/4-1/5+1/5+1/6-1/6-1/7
=1+2/3-1/7
=1+11/21
=32/21
1又1/3+7/12-9/20+11/30-13/42
=1+1/3+(1/3+1/4)-(1/4+1/5)+(1/5+1/6)-(1/6+1/7)
=1+1/3+1/3-1/7
=5/3-1/7
=35/21-3/21
=32/21
=32/21 即 1又11/21.