[(x+3y)(x-3y)-(x-3y)²]÷6y
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[(x+3y)(x-3y)-(x-3y)²]÷6y
[(x+3y)(x-3y)-(x-3y)²]÷6y
[(x+3y)(x-3y)-(x-3y)²]÷6y
[(x+3y)(x-3y)-(x-3y)²]÷6y
=[(x²-9y²)-(x²-6xy+9y²)]÷6y
=(6xy-18y²)÷6y
=[6y(x-3y)]÷6y
=x-3y
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