求助!分解因式2x的四次方+3x³-6x²-3x+4,谢谢!
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/02 07:57:15
![求助!分解因式2x的四次方+3x³-6x²-3x+4,谢谢!](/uploads/image/z/3737990-38-0.jpg?t=%E6%B1%82%E5%8A%A9%21%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F2x%E7%9A%84%E5%9B%9B%E6%AC%A1%E6%96%B9%2B3x%26%23179%3B-6x%26%23178%3B-3x%2B4%2C%E8%B0%A2%E8%B0%A2%21)
x){iJŧm//~:{=Fg<=ٚϦ6PS6453,u+Mt^lXD6IE_`gC%<gaTgTgma\gTik7irt
5Z Bը @B& Db&6yvP?ـ9Dy*5#T UB0C!^tM8=HH6vgX|>0H :ma
求助!分解因式2x的四次方+3x³-6x²-3x+4,谢谢!
求助!分解因式2x的四次方+3x³-6x²-3x+4,谢谢!
求助!分解因式2x的四次方+3x³-6x²-3x+4,谢谢!
原式=(2x^4-6x^2+4)+(3x^3-3x)=2(x^4-3x^2+2)+3x(x^2-1)
=2(x^2-1)(x^2-2)+3x(x^2-1)=(x+1)(x-1)(2x^2-4+3x)=(x+1)(x-1)(2x^2+3x-4)
2x的四次方+3x³-6x²-3x+4
=2x^4+3x³-6x²-3x+4
=2x^4-2x²+3x³-3x-4x²+4
=2x²(x²-1)+3x(x²-1)-4(x²-1)
=(x²-1)(2x²+3x-4)
=(x-1)(x+1)(2x²+3x-4)
还要继续吗?