(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值(2)(2x-1)²-x(1-2x)=0(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值解方程:(2)(2x-1)²-x(1-2x)=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 01:32:36
![(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值(2)(2x-1)²-x(1-2x)=0(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值解方程:(2)(2x-1)²-x(1-2x)=0](/uploads/image/z/3738289-49-9.jpg?t=%281%29%E6%8A%8A%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0y%3D3x%26%23178%3B-12x%2B3%E5%8C%96%E6%88%90%E9%A1%B6%E7%82%B9%2C%E5%B9%B6%E5%86%99%E5%87%BA%E5%9D%90%E6%A0%87%E3%80%81%E5%AF%B9%E7%A7%B0%E8%BD%B4%E5%92%8C%E6%9C%80%E5%80%BC%282%29%282x-1%29%26%23178%3B-x%EF%BC%881-2x%EF%BC%89%3D0%281%29%E6%8A%8A%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0y%3D3x%26%23178%3B-12x%2B3%E5%8C%96%E6%88%90%E9%A1%B6%E7%82%B9%EF%BC%8C%E5%B9%B6%E5%86%99%E5%87%BA%E5%9D%90%E6%A0%87%E3%80%81%E5%AF%B9%E7%A7%B0%E8%BD%B4%E5%92%8C%E6%9C%80%E5%80%BC%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%9A%282%29%282x-1%29%26%23178%3B-x%EF%BC%881-2x%EF%BC%89%3D0)
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(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值(2)(2x-1)²-x(1-2x)=0(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值解方程:(2)(2x-1)²-x(1-2x)=0
(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值(2)(2x-1)²-x(1-2x)=0
(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值
解方程:(2)(2x-1)²-x(1-2x)=0
(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值(2)(2x-1)²-x(1-2x)=0(1)把二次函数y=3x²-12x+3化成顶点,并写出坐标、对称轴和最值解方程:(2)(2x-1)²-x(1-2x)=0
(1)y=3(x^2-4x)+3=3(x^2-4x+4-4)+3=3(x^2-4x+4)-12+3=3(x-2)^2-9
对称轴x=2 图形画出来 最值就出来了 或者求导数判定增减性
(2)(2x-1)^2+x(2x-1)=(2x-1)(3x-1)=0
剩下的不用我写出来了吧