若(1/x)-(1/y)=2,求(3x-2xy-3y)除以(x-2xy-y)的值
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若(1/x)-(1/y)=2,求(3x-2xy-3y)除以(x-2xy-y)的值
若(1/x)-(1/y)=2,求(3x-2xy-3y)除以(x-2xy-y)的值
若(1/x)-(1/y)=2,求(3x-2xy-3y)除以(x-2xy-y)的值
1/x-1/y=2
同时乘以xy
y-x=2xy
同时乘以3
3y-3x=6xy
3x-3y=-6xy
(3x-2xy-3y)=-8xy
x-y=-2xy
(x-2xy-y)=-4xy
(3x-2xy-3y)除以(x-2xy-y)=2
把所求式上下处以XY
得(3/y-2-3/x)/(1/y-2-1/x)=8/4
上下同除以xy 就可以了
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