设集数A具有如下性质:①A的元素个数不超过3;②若a∈A,a≠1,则1/1-a ∈A.已知2∈A,求集合A.2∈A即a=2所以1/(1-2)=-1∈A则1/[1-(-1)]=1/2∈A所以1/(1-1/2)=2∈A形成循环所以A={2,-1,1/2}为什么要把2代入A啊,
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![设集数A具有如下性质:①A的元素个数不超过3;②若a∈A,a≠1,则1/1-a ∈A.已知2∈A,求集合A.2∈A即a=2所以1/(1-2)=-1∈A则1/[1-(-1)]=1/2∈A所以1/(1-1/2)=2∈A形成循环所以A={2,-1,1/2}为什么要把2代入A啊,](/uploads/image/z/3740794-34-4.jpg?t=%E8%AE%BE%E9%9B%86%E6%95%B0A%E5%85%B7%E6%9C%89%E5%A6%82%E4%B8%8B%E6%80%A7%E8%B4%A8%EF%BC%9A%E2%91%A0A%E7%9A%84%E5%85%83%E7%B4%A0%E4%B8%AA%E6%95%B0%E4%B8%8D%E8%B6%85%E8%BF%873%EF%BC%9B%E2%91%A1%E8%8B%A5a%E2%88%88A%2Ca%E2%89%A01%2C%E5%88%991%2F1-a+%E2%88%88A.%E5%B7%B2%E7%9F%A52%E2%88%88A%2C%E6%B1%82%E9%9B%86%E5%90%88A.2%E2%88%88A%E5%8D%B3a%3D2%E6%89%80%E4%BB%A51%2F%281-2%29%3D-1%E2%88%88A%E5%88%991%2F%5B1-%28-1%29%5D%3D1%2F2%E2%88%88A%E6%89%80%E4%BB%A51%2F%281-1%2F2%29%3D2%E2%88%88A%E5%BD%A2%E6%88%90%E5%BE%AA%E7%8E%AF%E6%89%80%E4%BB%A5A%3D%7B2%2C-1%2C1%2F2%7D%E4%B8%BA%E4%BB%80%E4%B9%88%E8%A6%81%E6%8A%8A2%E4%BB%A3%E5%85%A5A%E5%95%8A%2C)
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