已知a-b=2,ab=1,求多项式(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)

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已知a-b=2,ab=1,求多项式(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)
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已知a-b=2,ab=1,求多项式(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)
已知a-b=2,ab=1,求多项式(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)

已知a-b=2,ab=1,求多项式(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)
(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)
=-2ab+2a+3b-3ab-2b+2a-a-4b-ab
=(-2ab-3ab-ab)+(2a+2a-a)+(3b-2b-4b)
=-6ab+3a-3b
=-6ab+3(a-b)
=-6+6
=0


(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)
=-2ab+2a+3b-3ab-2b+2a-a-4b-ab
=-6ab+3a-3b
=-6ab+3(a-b)
=-6*1+3*2=12

(-2ab+2a+3b)-(3ab+2b-2a)-(a+4b+ab)=3a-3b-6ab=6-6=0