若方程4x²+(a²-3a-10)x+4a=0的两根互为相反数,则a=?
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若方程4x²+(a²-3a-10)x+4a=0的两根互为相反数,则a=?
若方程4x²+(a²-3a-10)x+4a=0的两根互为相反数,则a=?
若方程4x²+(a²-3a-10)x+4a=0的两根互为相反数,则a=?
有a²-3a-10=0
有俩根 a<0
a=-2
x1+x2=-(a²-3a-10)/8=0
x1*x2=a<0
a²-3a-10=(a-5)(a+2)=0
a=5 (a=-2 舍去)