(a^2+1)^2-4a(a^2+1)+4a^2 因式分解

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(a^2+1)^2-4a(a^2+1)+4a^2 因式分解
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(a^2+1)^2-4a(a^2+1)+4a^2 因式分解
(a^2+1)^2-4a(a^2+1)+4a^2 因式分解

(a^2+1)^2-4a(a^2+1)+4a^2 因式分解
(a^2+1)^2-4a(a^2+1)+4a^2
=(a^2+1-2a)^2
=(a-1)^4

(a^2+1)^2-4a(a^2+1)+4a^2
=(a^2+1-2a)^2

(a^2+1)^2-4a(a^2+1)+4a^2=(a^2+1-2a)^2=(a-1)^4

(a^2+1)^2-4a(a^2+1)+4a^2
=(a^2+1)^2-2*2a*(a^2+1)+(2a)^2
=(a^2+1-2a)^2
=[(a-1)^2]^2
=(a-1)^4

设a^2+1=a,2a=b
(a^2+1)^2-4a(a^2+1)+4a^2
=a^2-2ab+b^2
=(a-b)^2
=(a^2+1-2a)^2
=[(a-1)^2]^2
=(a-1)^4