化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)

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化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
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化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)

化简[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
=[2x/(x+2)(x-2)-1/(x-2)]*(x+2)/(x-1)
=(2x-x-2)/(x+2)(x-2)*(x+2)/(x-1)
=1/(x+2)*(x+2)/(x-1)
=1/(x-1)

1/（x-2）分子分母同时乘以（x+2）然后得[2x/x2-4-1/(x-2)}=(x-2)/x2-4=1/(x+2）
然后乘以x+2再除以x-1等于1/（x-1)

[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
={2x/[(x+2)(x-2)]-1/(x-2)}·(x+2)/(x-1)
={[2x-(x+2)]/[(x+2)(x-2)]}·(x+2)/(x-1)
={(x-2)/[(x+2)(x-2)]}·(x+2)/(x-1)
=[1/(x+2)]·(x+2)/(x-1)
=1/(x-1)

后面那框框的符号是什么？
[2x/(x2-4)-1/(x-2)]·(x+2)/(x-1)
=[x/(x-2)-1/(x-2)]·(x+2)/(x-1)
=[(x-1)/(x-2)]·(x+2)/(x-1)
=(x-2)/(x+2)

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