已知关于X的一元二次方程x^2+(m-1)x-2m^2+m=0(m为实数)有两个实数根x1 ,x2(1)当m为何值时x1≠x2(2)若x1^2+x2^2=2求M的值
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![已知关于X的一元二次方程x^2+(m-1)x-2m^2+m=0(m为实数)有两个实数根x1 ,x2(1)当m为何值时x1≠x2(2)若x1^2+x2^2=2求M的值](/uploads/image/z/3756536-8-6.jpg?t=%E5%B7%B2%E7%9F%A5%E5%85%B3%E4%BA%8EX%E7%9A%84%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bx%5E2%2B%28m-1%29x-2m%5E2%2Bm%3D0%EF%BC%88m%E4%B8%BA%E5%AE%9E%E6%95%B0%EF%BC%89%E6%9C%89%E4%B8%A4%E4%B8%AA%E5%AE%9E%E6%95%B0%E6%A0%B9x1+%2Cx2%EF%BC%881%EF%BC%89%E5%BD%93m%E4%B8%BA%E4%BD%95%E5%80%BC%E6%97%B6x1%E2%89%A0x2%EF%BC%882%EF%BC%89%E8%8B%A5x1%5E2%2Bx2%5E2%3D2%E6%B1%82M%E7%9A%84%E5%80%BC)
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