已知|3x+1|+(y-1)²=0,求(2x³+3x²)-(x³-3x²-y的二千零八次方)的值
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![已知|3x+1|+(y-1)²=0,求(2x³+3x²)-(x³-3x²-y的二千零八次方)的值](/uploads/image/z/3756743-71-3.jpg?t=%E5%B7%B2%E7%9F%A5%7C3x%2B1%7C%2B%EF%BC%88y-1%EF%BC%89%26%23178%3B%3D0%2C%E6%B1%82%EF%BC%882x%26%23179%3B%2B3x%26%23178%3B%EF%BC%89-%EF%BC%88x%26%23179%3B-3x%26%23178%3B-y%E7%9A%84%E4%BA%8C%E5%8D%83%E9%9B%B6%E5%85%AB%E6%AC%A1%E6%96%B9%EF%BC%89%E7%9A%84%E5%80%BC)
已知|3x+1|+(y-1)²=0,求(2x³+3x²)-(x³-3x²-y的二千零八次方)的值
已知|3x+1|+(y-1)²=0,求(2x³+3x²)-(x³-3x²-y的二千零八次方)的值
已知|3x+1|+(y-1)²=0,求(2x³+3x²)-(x³-3x²-y的二千零八次方)的值
|3x+1|+(y-1)²=0,
那么3x+1=0 y-1=0
x= -1/3 y=1
(2x³+3x²)-(x³-3x²-y的二千零八次方)
=2x³+3x²-x³+3x²+y^2008
=x³+6x²+y^2008
= -1/27+6×1/9+1
=44/27
|3x+1|+(y-1)²=0
3x+1=0,y-1=0
x=-1/3,y=1
(2x³+3x²)-(x³-3x²-y的二千零八次方)
=-2/27+3+1/27+3-1
=-1/27+5
|3x+1|+(y-1)²=0
则 3x+1=0 y-1=0
x=-1/3 y=1
(2x³+3x²)-(x³-3x²-y的二千零八次方)
=2x³+3x²-x³+3x²+y的二千零八次方
=x³+6x²+y的二千零八次方
=-1/27+2/3+1
=44/27
因为|3x+1|+(y-1)²=0,所以3x+1=0,且y-1=0,得出x=-1/3,y=1
之后就好算了,带入就行了答案是,44/27.
由|3x+1|+(y-1)²=0得3x+1=0,y-1=0
x=-1/3,y=1
y^2008即表示y的二千零八次方
要求的式子=(2x³+3x²)-(x³-3x²-y^2008)=2x³+3x²-x³+3x²+1=x^3+6x^2+1
=(-1/3)^3+6*(-1/3)^2+1=-1/27+2/3+1=44/27