已知x^2-5x+1=0,求x^2/(x^4+6x^2+1)的值.

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已知x^2-5x+1=0,求x^2/(x^4+6x^2+1)的值.
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已知x^2-5x+1=0,求x^2/(x^4+6x^2+1)的值.
已知x^2-5x+1=0,求x^2/(x^4+6x^2+1)的值.

已知x^2-5x+1=0,求x^2/(x^4+6x^2+1)的值.
x^2-5x+1=0
x-5+1/x=0 两边除以x
x+1/x=5
x²/(x^4+6x²+1)
=1/(x²+6+1/x²)
=1/[(x+1/x)²+4]
=1/29

x2次方=5x-1带入原方程化简得1/29