1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1

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1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1
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1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1
1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1
还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1

1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1
1,原不等式可化为log1/2(x^2-x-2)>log1/2〔2(x-1)〕
∴x^2-x-2<2(x-1) 即x²-3x<0
∴ 0<x<3
1,|x+1|0即(x+1)(x-2)(x-1)<0
用列表法(学过吧?查一下课本)得x0 等价于(x-3)(x+2)(x-1)²(x-4)>0
再用列表法得-2