1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1
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![1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1](/uploads/image/z/3760352-8-2.jpg?t=1.%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8Flog1%2F2%28x%5E2-x-2%29%3Elog1%2F2%28x-1%29-1%E8%BF%98%E6%9C%89%2C%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8F%3A1.%E7%BB%9D%E5%AF%B9%E5%80%BC%E4%B8%8Bx%2B10+3.%28x-3%29%28x%2B2%29%5E3%28x-1%29%5E2%28x-4%29%3E0+4.x%2F%28x%5E2-8x%2B15%29%3E%3D2+5.%E5%B7%B2%E7%9F%A5a1)
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1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1
1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1
还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1
1.解不等式log1/2(x^2-x-2)>log1/2(x-1)-1还有,解不等式:1.绝对值下x+10 3.(x-3)(x+2)^3(x-1)^2(x-4)>0 4.x/(x^2-8x+15)>=2 5.已知a1
1,原不等式可化为log1/2(x^2-x-2)>log1/2〔2(x-1)〕
∴x^2-x-2<2(x-1) 即x²-3x<0
∴ 0<x<3
1,|x+1|0即(x+1)(x-2)(x-1)<0
用列表法(学过吧?查一下课本)得x0 等价于(x-3)(x+2)(x-1)²(x-4)>0
再用列表法得-2