解方程:150²-x²=130²-(140-x)²

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/05 13:44:08
解方程:150²-x²=130²-(140-x)²
xRJ@ 3 C:1+/ҟU\&Y/ l 3U5nvjr$|8Mcr2t7/=y}z7BzJwaT;Y*<~Bl8E(p0eVOI&kPeI`K2h7͂bP %g>Z@m 6va elh[Zq!UJ 'F k4( e&qgiU@

解方程:150²-x²=130²-(140-x)²
解方程:150²-x²=130²-(140-x)²

解方程:150²-x²=130²-(140-x)²
答案:90
150²-x²=130²-(140-x)²
150²-130²=x²-(140-x)²
20*280=(2x-140)*140
5600/140=2x-140
x=90

150²-x²=130²-(140-x)²
(150+130)(130-150)=x ²-x²-280x+140²
280x=140×140+280×20
x=70+20
x=90

150²-x²=130²-(140-x)²
150²-x²=130²-140²+280x-x²
280x=150²+140²-130²
280x=25200
x=25200÷280
x=90

150²-x²=130²-(140-x)²
150²-130²=x²-(140-x)²
(150-130)(150+130) = (x-140+x)(x+140-x)
280*20=140(2x-140)
2x-140=2*20
x-70=20
x=90