已知方程4x^2-4xy+2y^2+2y+1=0,求x,y的值!各位大哥十万火急啊,请速速解答吧!

已知方程4x^2-4xy+2y^2+2y+1=0,求x,y的值!各位大哥十万火急啊,请速速解答吧!
已知方程4x^2-4xy+2y^2+2y+1=0,求x,y的值!
各位大哥十万火急啊,请速速解答吧!

已知方程4x^2-4xy+2y^2+2y+1=0,求x,y的值!各位大哥十万火急啊,请速速解答吧!
4x^2-4xy+2y^2+2y+1=0
(4x^2-4xy+y^2)+(y^2+2y+1)=0
(2x-y)^2+(y+1)^2=0
2x-y=0,y+1=0
x=-1/2,y=-1

4x^2-4xy+2y^2+2y+1=0
所以(4x^2-4xy+y^2)+(y^2+2y+1)=0
所以(2X-Y)^2+(Y+1)^2=0
所以Y=-1
所以X=1/2

原式等价于:(2x-y)^2+(y+1)^2=0
所以2x-y=0,y+1=0
y=-1,x=-1/2

4x^2-4xy+2y^2+2y+1=0,
4x^2-4xy+y^2+y^2+2y+1=0,
(2x-y)^2+(y+1)^2=0
2x-y=0并且 y+1=0
x=-1/2,y=-1