已知A/x+3 -B/2x-1=3x-5/(x+3(2x-1))求A,B,的值

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已知A/x+3 -B/2x-1=3x-5/(x+3(2x-1))求A,B,的值
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已知A/x+3 -B/2x-1=3x-5/(x+3(2x-1))求A,B,的值
已知A/x+3 -B/2x-1=3x-5/(x+3(2x-1))求A,B,的值

已知A/x+3 -B/2x-1=3x-5/(x+3(2x-1))求A,B,的值
(x+3)分之A-(2x-1)分之B =(x+3)(2x-1)分之3x-5
(x+3)(2x-1)分之[A(2x-1)-B(x+3)]=(x+3)(2x-1)分之3x-5
(x+3)(2x-1)分之[(2A-B)x-(A+3B)]=(x+3)(2x-1)分之3x-5
则2A-B=3,A+3B=5
解得A=2,B=1