求不定积分(2+x-x^2)^1/2dx

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 13:36:14
求不定积分(2+x-x^2)^1/2dx
x){Ɏާf=_iG=FqFqF)6IEi֓K*\ QU07T(+IKRJk:V+hXꛀeԔ -A ` % F%0Ͷ m % @y@Jj\g%E@) ]CM}cj D?꘥ hM/.H̳́x*`]88`ZKBuMtI{4l7

求不定积分(2+x-x^2)^1/2dx
求不定积分(2+x-x^2)^1/2dx

求不定积分(2+x-x^2)^1/2dx
令 x﹣1/2 = (3/2) sint,dx = (3/2) cost dt
| = ∫ (9/4) cos²t dt
= 9/8 ∫ (1+ cos2t) dt
= (9/8) { t + (1/2)sin2t } + C
= (9/8) arcsin(2x-1)/3 + (1/2) (x-1/2) √(2+x﹣x²) + C

积分:[(9/4)-(x-1/2)^2]^(1/2) dx
=sin^(-1)((x-1/2)/(3/2))
=sin^(-1)((2x-1)/3)