关于matlab/simulink仿真过程出现的inf和NaN问题!Derivative input 1 of at time 0.2686788627406385 is Inf or NaN.Stopping simulation.There may be a singularity in the solution.If not,try reducing the step size (either by reducing the fixed st
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/29 00:00:38
![关于matlab/simulink仿真过程出现的inf和NaN问题!Derivative input 1 of at time 0.2686788627406385 is Inf or NaN.Stopping simulation.There may be a singularity in the solution.If not,try reducing the step size (either by reducing the fixed st](/uploads/image/z/3766371-51-1.jpg?t=%E5%85%B3%E4%BA%8Ematlab%2Fsimulink%E4%BB%BF%E7%9C%9F%E8%BF%87%E7%A8%8B%E5%87%BA%E7%8E%B0%E7%9A%84inf%E5%92%8CNaN%E9%97%AE%E9%A2%98%21Derivative+input+1+of+at+time+0.2686788627406385+is+Inf+or+NaN.Stopping+simulation.There+may+be+a+singularity+in+the+solution.If+not%2Ctry+reducing+the+step+size+%28either+by+reducing+the+fixed+st)
关于matlab/simulink仿真过程出现的inf和NaN问题!Derivative input 1 of at time 0.2686788627406385 is Inf or NaN.Stopping simulation.There may be a singularity in the solution.If not,try reducing the step size (either by reducing the fixed st
关于matlab/simulink仿真过程出现的inf和NaN问题!
Derivative input 1 of at time 0.2686788627406385 is Inf or NaN.Stopping simulation.There may be a singularity in the solution.If not,try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances).修改了误差容限和步长,要么有同样的问题要么一直running.请问该如何解决.
关于matlab/simulink仿真过程出现的inf和NaN问题!Derivative input 1 of at time 0.2686788627406385 is Inf or NaN.Stopping simulation.There may be a singularity in the solution.If not,try reducing the step size (either by reducing the fixed st
在回路反馈端加一个memory就可以了!