已知x²-4x-1=0,求代数式x²(x-4)²-y(x²-1)+4xy的值
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已知x²-4x-1=0,求代数式x²(x-4)²-y(x²-1)+4xy的值
已知x²-4x-1=0,求代数式x²(x-4)²-y(x²-1)+4xy的值
已知x²-4x-1=0,求代数式x²(x-4)²-y(x²-1)+4xy的值
∴x²-4x-1=0
x(x-4)=1
∴(x-4)=1/x
x²-1=4x
∴x²(x-4)²-y(x²-1)+4xy
=x²×(1/x)²-y×4x+4xy
=x²×1/x²-4xy+4xy
=1