分解因式 (1+y)²-2x²(1-y²)+x的4次方(1-y)²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 18:34:17
![分解因式 (1+y)²-2x²(1-y²)+x的4次方(1-y)²](/uploads/image/z/3769074-18-4.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F+%281%2By%29%26%23178%3B-2x%26%23178%3B%281-y%26%23178%3B%29%2Bx%E7%9A%844%E6%AC%A1%E6%96%B9%281-y%29%26%23178%3B)
x){b⧳<ӯa]lhnakTahVBXg<[ٴ aR"}_`gC=Q7H(Z"H,F3(KbUIJmC~qAbȳ }
分解因式 (1+y)²-2x²(1-y²)+x的4次方(1-y)²
分解因式 (1+y)²-2x²(1-y²)+x的4次方(1-y)²
分解因式 (1+y)²-2x²(1-y²)+x的4次方(1-y)²
(1+y)²-2x²(1-y²)+x的4次方(1-y)²
=(1+y)^2-2[(x^2)(1-y)](1+y)+[(x^2)(1-y)]^2
=[(1+y)-(x^2)(1-y)]^2
=[(x^2)y-x^2+y+1]^2