已知sin(x+y)/cos(x-y)=m/n,则tanx/tany=?
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已知sin(x+y)/cos(x-y)=m/n,则tanx/tany=?
已知sin(x+y)/cos(x-y)=m/n,则tanx/tany=?
已知sin(x+y)/cos(x-y)=m/n,则tanx/tany=?
要求tanx/tany则x,y≠π/2+kπ,且y≠kπ(k为整数),则cosxcosy≠0
sin(x+y)/cos(x-y)=m/n
(sinxcosy+cosxsiny)/(cosxcosy+sinxsiny)=m/n
(tanx+tany)/(1+tanxtany)=m/n(等式左边同除以cosxcosy)
总觉得好像不是这么求、、、、我记得要画图 画图特省事。。。但是具体的真忘了。。抱歉
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已知sin(x+y)/cos(x-y)=m/n,则tanx/tany=?
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