x²+﹙2i-1﹚x+3m-1=0有实根,求实数m的值
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x²+﹙2i-1﹚x+3m-1=0有实根,求实数m的值
x²+﹙2i-1﹚x+3m-1=0有实根,求实数m的值
x²+﹙2i-1﹚x+3m-1=0有实根,求实数m的值
将方程:x平方-(2i-1)x+3m-i=0
改写为:[x^2 + x + 3m] - i * [2x + 1] = 0
因为有实根,因此:2x + 1 = 0
即:实根为:x = -1/2
代入方程的实部:(-1/2)^2 + (-1/2) + 3m = 0
得:m = 1/12