作业帮求函数y=log1/2[2sin(2x+π/3)-1]的单调区间,请写出过程.
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![求函数y=log1/2[2sin(2x+π/3)-1]的单调区间,请写出过程.](/uploads/image/z/3778365-21-5.jpg?t=%E6%B1%82%E5%87%BD%E6%95%B0y%3Dlog1%2F2%5B2sin%282x%2B%CF%80%2F3%29-1%5D%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4%2C%E8%AF%B7%E5%86%99%E5%87%BA%E8%BF%87%E7%A8%8B.)
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求函数y=log1/2[2sin(2x+π/3)-1]的单调区间,请写出过程.
求函数y=log1/2[2sin(2x+π/3)-1]的单调区间,请写出过程.
求函数y=log1/2[2sin(2x+π/3)-1]的单调区间,请写出过程.
定义域 2sin(2x+π/3)-1>0 sin(2x+π/3)>1/2
2kπ+π/6