已知a.b.c分别是△ABC的三个内角,A.B.C所对的边①若△ABC的面积S△ABC=根号3/2 C=2 A=60°求a.b的值②若a=ccosB且b=csinA判断△ABC的形状.(这是原题)
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![已知a.b.c分别是△ABC的三个内角,A.B.C所对的边①若△ABC的面积S△ABC=根号3/2 C=2 A=60°求a.b的值②若a=ccosB且b=csinA判断△ABC的形状.(这是原题)](/uploads/image/z/3785163-51-3.jpg?t=%E5%B7%B2%E7%9F%A5a.b.c%E5%88%86%E5%88%AB%E6%98%AF%E2%96%B3ABC%E7%9A%84%E4%B8%89%E4%B8%AA%E5%86%85%E8%A7%92%2CA.B.C%E6%89%80%E5%AF%B9%E7%9A%84%E8%BE%B9%E2%91%A0%E8%8B%A5%E2%96%B3ABC%E7%9A%84%E9%9D%A2%E7%A7%AFS%E2%96%B3ABC%3D%E6%A0%B9%E5%8F%B73%2F2+C%3D2+A%3D60%C2%B0%E6%B1%82a.b%E7%9A%84%E5%80%BC%E2%91%A1%E8%8B%A5a%3DccosB%E4%B8%94b%3DcsinA%E5%88%A4%E6%96%AD%E2%96%B3ABC%E7%9A%84%E5%BD%A2%E7%8A%B6.%EF%BC%88%E8%BF%99%E6%98%AF%E5%8E%9F%E9%A2%98%EF%BC%89)
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