1/2(y+1)+1/3(y+2)+1/4(y+3)-3=0不需要解了,我看了答案,我只想大家帮我分析一下[1/2(y+1)-1]+[1/3(y+2)-1]+[1/4(y+3)-3]=0即1/2(y-1)+1/3(y-1)+1/4(y-1)=0 ——就是这步,我已经说了,答案都写出来了!还需要你们化简
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/20 11:31:03
![1/2(y+1)+1/3(y+2)+1/4(y+3)-3=0不需要解了,我看了答案,我只想大家帮我分析一下[1/2(y+1)-1]+[1/3(y+2)-1]+[1/4(y+3)-3]=0即1/2(y-1)+1/3(y-1)+1/4(y-1)=0 ——就是这步,我已经说了,答案都写出来了!还需要你们化简](/uploads/image/z/3785184-0-4.jpg?t=1%2F2%28y%2B1%29%2B1%2F3%28y%2B2%29%2B1%2F4%28y%2B3%29-3%3D0%E4%B8%8D%E9%9C%80%E8%A6%81%E8%A7%A3%E4%BA%86%2C%E6%88%91%E7%9C%8B%E4%BA%86%E7%AD%94%E6%A1%88%2C%E6%88%91%E5%8F%AA%E6%83%B3%E5%A4%A7%E5%AE%B6%E5%B8%AE%E6%88%91%E5%88%86%E6%9E%90%E4%B8%80%E4%B8%8B%5B1%2F2%28y%2B1%29-1%5D%2B%5B1%2F3%28y%2B2%29-1%5D%2B%5B1%2F4%28y%2B3%29-3%5D%3D0%E5%8D%B31%2F2%28y-1%29%2B1%2F3%28y-1%29%2B1%2F4%28y-1%29%3D0+%E2%80%94%E2%80%94%E5%B0%B1%E6%98%AF%E8%BF%99%E6%AD%A5%2C%E6%88%91%E5%B7%B2%E7%BB%8F%E8%AF%B4%E4%BA%86%EF%BC%8C%E7%AD%94%E6%A1%88%E9%83%BD%E5%86%99%E5%87%BA%E6%9D%A5%E4%BA%86%EF%BC%81%E8%BF%98%E9%9C%80%E8%A6%81%E4%BD%A0%E4%BB%AC%E5%8C%96%E7%AE%80)
1/2(y+1)+1/3(y+2)+1/4(y+3)-3=0不需要解了,我看了答案,我只想大家帮我分析一下[1/2(y+1)-1]+[1/3(y+2)-1]+[1/4(y+3)-3]=0即1/2(y-1)+1/3(y-1)+1/4(y-1)=0 ——就是这步,我已经说了,答案都写出来了!还需要你们化简
1/2(y+1)+1/3(y+2)+1/4(y+3)-3=0
不需要解了,我看了答案,我只想大家帮我分析一下
[1/2(y+1)-1]+[1/3(y+2)-1]+[1/4(y+3)-3]=0
即1/2(y-1)+1/3(y-1)+1/4(y-1)=0 ——就是这步,
我已经说了,答案都写出来了!还需要你们化简吗,就是告诉我那一步为什么这样写,不过也谢谢你
1/2(y+1)+1/3(y+2)+1/4(y+3)-3=0不需要解了,我看了答案,我只想大家帮我分析一下[1/2(y+1)-1]+[1/3(y+2)-1]+[1/4(y+3)-3]=0即1/2(y-1)+1/3(y-1)+1/4(y-1)=0 ——就是这步,我已经说了,答案都写出来了!还需要你们化简
你的题目这么写容易造成别人的误1/2(y+1)写成(y+1)/2更确切.
1/2(y+1)+1/3(y+2)+1/4(y+3)-3
=(y+1)/2+(y+2)/3+(y+3)/4-3
=[(y+1)/2-1+(y+2)/3-1+(y+3)/4-1]
=[(y+1)/2-(2/2)+(y+2)/3-(3/3)+(y+3)/4-(4/4)]
=(y+1-2)/2+(y+2-3)/3+(y+3-4)/4
=(y-1)/2+(y-1)/3+(y-1)/4
其实你看不懂的那步,简单的说就是把3拆成3个1,然后分别通分计算
把这个式子化简,最后可求出1/2y+1/3y+1/4y-1/2-1/3-1/4=0。那么13/12y-13/12=0,则y为1。