若a>b>0>c,a+b+c=0,且|b+1|=|c+1|,求-a平方+2b-c-(a-4c-b)的值|b+1|=|c+1|,则有:b+1=-c-1 得:b+c=-2又:a+b+c=0 则有:a=2所以:-a平方+2b-c-(a-4c-b)=-a^2+2b-c-a+4c+b=-a^2-a+3(b+c)=-4-2-6=-12
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![若a>b>0>c,a+b+c=0,且|b+1|=|c+1|,求-a平方+2b-c-(a-4c-b)的值|b+1|=|c+1|,则有:b+1=-c-1 得:b+c=-2又:a+b+c=0 则有:a=2所以:-a平方+2b-c-(a-4c-b)=-a^2+2b-c-a+4c+b=-a^2-a+3(b+c)=-4-2-6=-12](/uploads/image/z/3788020-28-0.jpg?t=%E8%8B%A5a%3Eb%3E0%3Ec%2Ca%2Bb%2Bc%3D0%2C%E4%B8%94%7Cb%2B1%7C%3D%7Cc%2B1%7C%2C%E6%B1%82-a%E5%B9%B3%E6%96%B9%2B2b-c-%28a-4c-b%29%E7%9A%84%E5%80%BC%7Cb%2B1%7C%3D%7Cc%2B1%7C%2C%E5%88%99%E6%9C%89%EF%BC%9Ab%2B1%3D-c-1+%E5%BE%97%EF%BC%9Ab%2Bc%3D-2%E5%8F%88%EF%BC%9Aa%2Bb%2Bc%3D0+%E5%88%99%E6%9C%89%EF%BC%9Aa%3D2%E6%89%80%E4%BB%A5%EF%BC%9A-a%E5%B9%B3%E6%96%B9%2B2b-c-%28a-4c-b%29%3D-a%5E2%2B2b-c-a%2B4c%2Bb%3D-a%5E2-a%2B3%28b%2Bc%29%3D-4-2-6%3D-12)
若a>b>0>c,a+b+c=0,且|b+1|=|c+1|,求-a平方+2b-c-(a-4c-b)的值|b+1|=|c+1|,则有:b+1=-c-1 得:b+c=-2又:a+b+c=0 则有:a=2所以:-a平方+2b-c-(a-4c-b)=-a^2+2b-c-a+4c+b=-a^2-a+3(b+c)=-4-2-6=-12
若a>b>0>c,a+b+c=0,且|b+1|=|c+1|,求-a平方+2b-c-(a-4c-b)的值
|b+1|=|c+1|,则有:b+1=-c-1 得:b+c=-2
又:a+b+c=0 则有:a=2
所以:
-a平方+2b-c-(a-4c-b)
=-a^2+2b-c-a+4c+b
=-a^2-a+3(b+c)
=-4-2-6
=-12
若a>b>0>c,a+b+c=0,且|b+1|=|c+1|,求-a平方+2b-c-(a-4c-b)的值|b+1|=|c+1|,则有:b+1=-c-1 得:b+c=-2又:a+b+c=0 则有:a=2所以:-a平方+2b-c-(a-4c-b)=-a^2+2b-c-a+4c+b=-a^2-a+3(b+c)=-4-2-6=-12
|b+1|=|c+1|,则有:b+1=-c-1 得:b+c=-2
又:a+b+c=0 则有:a=2
所以:
-a平方+2b-c-(a-4c-b)
=-a^2+2b-c-a+4c+b
=-a^2-a+3(b+c)
=-4-2+6
=0
a=-b-c,由|b+1|=|c+1|得b=-c或b+c=-2,代入式中得(b+c)的平方+2b-c-(-b-c-4c-b)=(b+c)的平方+4(b+c)=0或者-4.
即当b=-c时答案为0
当b+c=-2时答案为-4
g