已知x,y,z,满足根号(3x-2y-4)+根号(2x-7y+3)=根号(2x-4y-z)*根号(-x/2 +2y)求z的值?
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![已知x,y,z,满足根号(3x-2y-4)+根号(2x-7y+3)=根号(2x-4y-z)*根号(-x/2 +2y)求z的值?](/uploads/image/z/379748-20-8.jpg?t=%E5%B7%B2%E7%9F%A5x%2Cy%2Cz%2C%E6%BB%A1%E8%B6%B3%E6%A0%B9%E5%8F%B7%EF%BC%883x-2y-4%EF%BC%89%2B%E6%A0%B9%E5%8F%B7%EF%BC%882x-7y%2B3%EF%BC%89%3D%E6%A0%B9%E5%8F%B7%EF%BC%882x-4y-z%EF%BC%89%2A%E6%A0%B9%E5%8F%B7%EF%BC%88-x%2F2+%2B2y%EF%BC%89%E6%B1%82z%E7%9A%84%E5%80%BC%3F)
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已知x,y,z,满足根号(3x-2y-4)+根号(2x-7y+3)=根号(2x-4y-z)*根号(-x/2 +2y)求z的值?
已知x,y,z,满足根号(3x-2y-4)+根号(2x-7y+3)=根号(2x-4y-z)*根号(-x/2 +2y)求z的值?
已知x,y,z,满足根号(3x-2y-4)+根号(2x-7y+3)=根号(2x-4y-z)*根号(-x/2 +2y)求z的值?
由题可知:
3x-2y-4>=0 ===>3x-2y>=4 ===>9x-6y>=12,
2x-7y+3>=0 ===>2x-7y>=-3 ===>8x-28y>=-12,
所以17x-34y>=0,
x-2y>=0,
又-x+2y>=0 ===>x-2y=0 ===>x-2y>=z/2,
所以z