((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急
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![((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急](/uploads/image/z/380112-24-2.jpg?t=%28%283x-7%29%5E2-%28x%2B5%29%5E2%29%2F%284x-24%29.2%2C%28%28x%5E2%2B1%29%5E2-4x%28x%5E2%2B1%29%2B4x%5E2%29%2F%28x-1%29%5E2+%E8%AE%A1%E7%AE%97%28%283x-7%29%5E2-%28x%2B5%29%5E2%29%2F%284x-24%29.2%2C%28%28x%5E2%2B1%29%5E2-4x%28x%5E2%2B1%29%2B4x%5E2%29%2F%28x-1%29%5E2+%E8%AE%A1%E7%AE%97+%E6%80%A5)
((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急
((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算
((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急
((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急
((3x-7)^2-(x+5)^2)/(4x-24).
=(3x-7+x+5)(3x-7-x-5)/(4x-24)
=(4x-2)(2x-12)/(4x-24)
=4(2x-1)(x-6)/4(x-6)
=2x-1
((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2
=[(x^2+1)-2]^2/(x-1)^2
=(x^2-1)^2/(x-1)^2
=(x-1)^2(x+1)^2/(x-1)^2
=(x+1)^2
=x^2+2x+1
一
原式等于(3x-7-x-5)(3x-7+x+5)/(4x-24)
=(2x-12)(4x-2)/(4x-24)
=2x-1
二
原式等于(x~2+1-2x~2)~2/(x-1)~2
=(1-x~2)~2/(x-1)~2
=(x-1)~2(x+1)~2/(x-1)~2
=(x+1)~2
第一题
[(3x-7)^2-(x+5)^2]/(4x-24)
利用公式a^2-b^2=(a+b)(a-b)
=[(3x-7)+(x+5)][(3x-7)-(x+5)]/(4x-24)
化简得 (4x-2)(2x-12)/(4x-24)
=(4x-2)(2x-12)/[2(2x-12)]
=(4x-2)/2
=2x-1
第二题
全部展开
第一题
[(3x-7)^2-(x+5)^2]/(4x-24)
利用公式a^2-b^2=(a+b)(a-b)
=[(3x-7)+(x+5)][(3x-7)-(x+5)]/(4x-24)
化简得 (4x-2)(2x-12)/(4x-24)
=(4x-2)(2x-12)/[2(2x-12)]
=(4x-2)/2
=2x-1
第二题
原公式={〔(x^2+1)-2x]^2}/[(x-1)^2]
={[(x-1)^2]^2}/[(x-1)^2]
=[(x-1)^4]/[(x-1)^2]
=(x-1)^2
可以把x^2+1 看作A,把2x看作B
A^2-2AB-B^2=(A-B)^2
收起