((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急

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((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急
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((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急
((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算
((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急

((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算((3x-7)^2-(x+5)^2)/(4x-24).2,((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2 计算 急
((3x-7)^2-(x+5)^2)/(4x-24).
=(3x-7+x+5)(3x-7-x-5)/(4x-24)
=(4x-2)(2x-12)/(4x-24)
=4(2x-1)(x-6)/4(x-6)
=2x-1
((x^2+1)^2-4x(x^2+1)+4x^2)/(x-1)^2
=[(x^2+1)-2]^2/(x-1)^2
=(x^2-1)^2/(x-1)^2
=(x-1)^2(x+1)^2/(x-1)^2
=(x+1)^2
=x^2+2x+1

一
原式等于（3x-7-x-5）（3x-7+x+5）/（4x-24）
=（2x-12）（4x-2）/（4x-24）
=2x-1
二
原式等于（x~2+1-2x~2）~2/（x-1）~2
=（1-x~2）~2/（x-1）~2
=（x-1）~2（x+1）~2/（x-1）~2
=（x+1）~2

第一题
[(3x-7)^2-(x+5)^2]/(4x-24)
利用公式a^2-b^2=(a+b)(a-b)
=[(3x-7)+(x+5)][(3x-7)-(x+5)]/(4x-24)
化简得 （4x-2)(2x-12)/(4x-24)
=（4x-2)(2x-12)/[2(2x-12)]
=(4x-2)/2
=2x-1
第二题

全部展开

第一题
[(3x-7)^2-(x+5)^2]/(4x-24)
利用公式a^2-b^2=(a+b)(a-b)
=[(3x-7)+(x+5)][(3x-7)-(x+5)]/(4x-24)
化简得 （4x-2)(2x-12)/(4x-24)
=（4x-2)(2x-12)/[2(2x-12)]
=(4x-2)/2
=2x-1
第二题
原公式＝{〔(x^2+1)-2x]^2}/[(x-1)^2]
={[(x-1)^2]^2}/[(x-1)^2]
=[(x-1)^4]/[(x-1)^2]
=(x-1)^2
可以把x^2+1 看作A，把2x看作B
A^2-2AB-B^2=(A-B)^2

收起

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