用平方差公式解答(1) (4+2x)(2-x) (2) (x+二分之一)(x²+四分之一)(x-二分之一)(x的四次方+十六分之一) 先化简,后求值(1) (2x+1)(x-2)-(-3x+1)(-3x-1),其中x=-2(2) 2x²-(x+y)(x-y)-2(y+1)
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![用平方差公式解答(1) (4+2x)(2-x) (2) (x+二分之一)(x²+四分之一)(x-二分之一)(x的四次方+十六分之一) 先化简,后求值(1) (2x+1)(x-2)-(-3x+1)(-3x-1),其中x=-2(2) 2x²-(x+y)(x-y)-2(y+1)](/uploads/image/z/3806309-29-9.jpg?t=%E7%94%A8%E5%B9%B3%E6%96%B9%E5%B7%AE%E5%85%AC%E5%BC%8F%E8%A7%A3%E7%AD%94%EF%BC%881%EF%BC%89+%284%2B2x%29%282-x%29+%EF%BC%882%EF%BC%89+%EF%BC%88x%2B%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80%EF%BC%89%EF%BC%88x%26%23178%3B%2B%E5%9B%9B%E5%88%86%E4%B9%8B%E4%B8%80%EF%BC%89%EF%BC%88x-%E4%BA%8C%E5%88%86%E4%B9%8B%E4%B8%80%EF%BC%89%EF%BC%88x%E7%9A%84%E5%9B%9B%E6%AC%A1%E6%96%B9%2B%E5%8D%81%E5%85%AD%E5%88%86%E4%B9%8B%E4%B8%80%EF%BC%89+%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%90%8E%E6%B1%82%E5%80%BC%EF%BC%881%EF%BC%89+%EF%BC%882x%2B1%29%28x-2%29-%28-3x%2B1%29%28-3x-1%29%2C%E5%85%B6%E4%B8%ADx%3D-2%282%29+2x%26%23178%3B-%28x%2By%29%28x-y%29-2%28y%2B1%29)
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