m²=2n+1,4n²=m+1(m不等于2n) 求(1)m+2n;(2)4n³-mn+2n²
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 02:33:39
xj1_ DwQ}¢/ ^l
SO{كz[tF+8D^7#oT*:`|N÷TFHq) K$Y<Ȓ'g76jӇ\%Zqpdpj:;(T7@[V>+zat-"CLŝ)e܌ S\\F>{@,Rx^|,|ek^Jט
m²=2n+1,4n²=m+1(m不等于2n) 求(1)m+2n;(2)4n³-mn+2n²
m²=2n+1,4n²=m+1(m不等于2n) 求(1)m+2n;(2)4n³-mn+2n²
m²=2n+1,4n²=m+1(m不等于2n) 求(1)m+2n;(2)4n³-mn+2n²
两式相减,m^2-4n^2=2n-m
(m+2n)(m-2n)+m-2n=0
(m-2n)(m+2n+1)=0
因为m-2n≠0
所以m+2n=-1
两式相加,m^2+4n^2=m+2n+2=1
(m+2n)^2-4mn=1
mn=0
所以4n^3-mn+2n^2=2n^2(2n+1)=2n^2*m^2=2(mn)^2=0
太简单