(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3a...(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3ac,求该双
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![(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3a...(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3ac,求该双](/uploads/image/z/3813020-44-0.jpg?t=%281%2F2%29%E5%8F%8C%E6%9B%B2%E7%BA%BFX2%2Fa2-y2%2Fb2%3D1%E5%8F%B3%E7%84%A6%E7%82%B9%E4%B8%BAF%2C%E7%84%A6%E8%B7%9D%E4%B8%BA2c%2C%E5%B7%A6%E9%A1%B6%E7%82%B9%E4%B8%BAA%2C%E8%99%9A%E8%BD%B4%E7%9A%84%E4%B8%8A%E7%AB%AF%E7%82%B9%E4%B8%BAB%280%2Cb%29%2C%E8%8B%A5BA%E5%90%91%E9%87%8F%2ABF%E5%90%91%E9%87%8F%3D3a...%281%2F2%29%E5%8F%8C%E6%9B%B2%E7%BA%BFX2%2Fa2-y2%2Fb2%3D1%E5%8F%B3%E7%84%A6%E7%82%B9%E4%B8%BAF%2C%E7%84%A6%E8%B7%9D%E4%B8%BA2c%2C%E5%B7%A6%E9%A1%B6%E7%82%B9%E4%B8%BAA%2C%E8%99%9A%E8%BD%B4%E7%9A%84%E4%B8%8A%E7%AB%AF%E7%82%B9%E4%B8%BAB%280%2Cb%29%2C%E8%8B%A5BA%E5%90%91%E9%87%8F%2ABF%E5%90%91%E9%87%8F%3D3ac%2C%E6%B1%82%E8%AF%A5%E5%8F%8C)
(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3a...(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3ac,求该双
(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3a...
(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3ac,求该双曲
(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3a...(1/2)双曲线X2/a2-y2/b2=1右焦点为F,焦距为2c,左顶点为A,虚轴的上端点为B(0,b),若BA向量*BF向量=3ac,求该双
BA向量(-a,-b),BF向量=(c,-b)
所以-ac+b^2=3ac
b^2=4ac
c^2=a^2+b^2=a^2+4ac
两边同时除以a^2
e^2-4e+1=0
e=2+√3>1
BA=(-a,-b) BF=(c,-b)
BA*BF=-ac+b^2=3ac b^2=c^2-a^2=4ac
在c^2-a^2=4ac中,两边除a^2得:e^2-4e-1=0 解得:e=2-根号2
BA=(-a,-b),BF=(c,-b),则BA*BF=3ac即:-ac+b²=3ac,b²=4ac,则:c²-a²=4ac,两边除以a²,得:(c/a)²-4(c/a)-1=0,得:e²-4e-1=0,e=2+√5
BA=(-a,-b) BF=(c,-b)
BA*BF=-ac+b^2=3ac b^2=c^2-a^2=4ac
在c^2-a^2=4ac中,两边除a^2得:e^2-4e-1=0 解得:1.e=2-根号5(舍去,e>1)。2.e=2+根号5
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