设函数f(x)=(x²+3x+m)e^-x(其中m∈R,e是自然对数的底数)(1)若m=3,求曲线y=f(x)在点(0,f(0))处的切线方程;(2)若函数f(x)在(-∞,0)上有2个极值点.①求实数m的范围;②证
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![设函数f(x)=(x²+3x+m)e^-x(其中m∈R,e是自然对数的底数)(1)若m=3,求曲线y=f(x)在点(0,f(0))处的切线方程;(2)若函数f(x)在(-∞,0)上有2个极值点.①求实数m的范围;②证](/uploads/image/z/3813294-30-4.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3D%EF%BC%88x%26%23178%3B%2B3x%2Bm%EF%BC%89e%5E-x%EF%BC%88%E5%85%B6%E4%B8%ADm%E2%88%88R%2Ce%E6%98%AF%E8%87%AA%E7%84%B6%E5%AF%B9%E6%95%B0%E7%9A%84%E5%BA%95%E6%95%B0%EF%BC%89%EF%BC%881%EF%BC%89%E8%8B%A5m%3D3%2C%E6%B1%82%E6%9B%B2%E7%BA%BFy%3Df%EF%BC%88x%EF%BC%89%E5%9C%A8%E7%82%B9%EF%BC%880%2Cf%EF%BC%880%EF%BC%89%EF%BC%89%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%EF%BC%9B%EF%BC%882%EF%BC%89%E8%8B%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E5%9C%A8%EF%BC%88-%E2%88%9E%2C0%EF%BC%89%E4%B8%8A%E6%9C%892%E4%B8%AA%E6%9E%81%E5%80%BC%E7%82%B9.%E2%91%A0%E6%B1%82%E5%AE%9E%E6%95%B0m%E7%9A%84%E8%8C%83%E5%9B%B4%EF%BC%9B%E2%91%A1%E8%AF%81)
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