f(x/x-6)=x²+2x-1 ,试求 f(1/3)之值.
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f(x/x-6)=x²+2x-1 ,试求 f(1/3)之值.
f(x/x-6)=x²+2x-1 ,试求 f(1/3)之值.
f(x/x-6)=x²+2x-1 ,试求 f(1/3)之值.
令x=-3
则x/(x-6)=1/3
所以,
f(1/3)=(-3)的平方+2·(-3)-1
=9-6-1
=2
x/(x-6)=1/3
(3x-x+6)/3(x-6)=0
(2x+6)/3(x-6)=0
6(x+3)(x-6)=0
所以x1=-3 x2=6
所以f(1/3)=(-3)^2+2*(-3)-1=9-6-1=2
或者f(1/3)=6^2+2*6-1=36+12-1=47