作业帮[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)] 这个等于-1/2是怎么算的?
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/19 18:23:04
![[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)] 这个等于-1/2是怎么算的?](/uploads/image/z/3817087-7-7.jpg?t=%5B%28x%26%23178%3B-1%29%26%23178%3B%2B%282x%2B1%29%26%23178%3B-%28x%26%23178%3B%2Bx%2B1%29%26%23178%3B%5D%2F%5B2%28x%26%23178%3B-1%29%282x%2B1%29%5B%28x%26%23178%3B-1%29%26%23178%3B%2B%282x%2B1%29%26%23178%3B-%28x%26%23178%3B%2Bx%2B1%29%26%23178%3B%5D%2F%5B2%28x%26%23178%3B-1%29%282x%2B1%29%5D+%E8%BF%99%E4%B8%AA%E7%AD%89%E4%BA%8E-1%2F2%E6%98%AF%E6%80%8E%E4%B9%88%E7%AE%97%E7%9A%84%3F)
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[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)] 这个等于-1/2是怎么算的?
[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)
[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)] 这个等于-1/2是怎么算的?
[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)[(x²-1)²+(2x+1)²-(x²+x+1)²]/[2(x²-1)(2x+1)] 这个等于-1/2是怎么算的?
其实你看到这个题目和答案,就可以想到,通过-(x²+x+1)²来合并拆分,与分母相互约去.
或者更简单,不用想的就是将分子每个都拆开,然后与分母相约.