作业帮若a²+a-3=0,求a⁴+2a³-a-1
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/04 09:34:31
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若a²+a-3=0,求a⁴+2a³-a-1
若a²+a-3=0,求a⁴+2a³-a-1
若a²+a-3=0,求a⁴+2a³-a-1
a²+a=3
原式=a⁴+a³+a³-a-1
=a²(a²+a)+a³-a-1
=3a²+a³-a-1
=a³+a²+2a²-a-1
=a(a²+a)+2a²-a-1
=3a+2a²-a-1
=2(a²+a)-1
=2×3-1
=5
a²+a-3=0
则
a²+a=3
则
原式
=a⁴+2a³-a-1
=a²(a²+1)+a³-a-1
=3a²+a³-a-1
=a(a²+a)+2a²-a-1
=3a+2a²-a-1
=2a²+2a-1
=2(a²+a)-1
=2*3-1
=5
∵a²+a-3=0
a²+a=3
∴a⁴+2a³-a-1
=a²(a²+a)+a³-a-1
=a³+3a³-a-1
=a(a²+a)+2a²-a-1
=2a²+3a-a-1
=2(a²+a)-1
=6-1
=5