将圆x2+y2+2x-2y=0按向量a=(1,-1)平移得到圆O(O为原点),直线l与圆O相交于A,B两点,若在圆O上存在点C,使OC+OA+OB=0,且OC=λa,求
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![将圆x2+y2+2x-2y=0按向量a=(1,-1)平移得到圆O(O为原点),直线l与圆O相交于A,B两点,若在圆O上存在点C,使OC+OA+OB=0,且OC=λa,求](/uploads/image/z/3818835-27-5.jpg?t=%E5%B0%86%E5%9C%86x%26%2357355%3B2%2By%26%2357355%3B2%2B2x-2y%3D0%E6%8C%89%E5%90%91%E9%87%8Fa%3D%281%2C-1%29%E5%B9%B3%E7%A7%BB%E5%BE%97%E5%88%B0%E5%9C%86O%EF%BC%88O%E4%B8%BA%E5%8E%9F%E7%82%B9%EF%BC%89%2C%E7%9B%B4%E7%BA%BFl%E4%B8%8E%E5%9C%86O%E7%9B%B8%E4%BA%A4%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E8%8B%A5%E5%9C%A8%E5%9C%86O%E4%B8%8A%E5%AD%98%E5%9C%A8%E7%82%B9C%2C%E4%BD%BF%26%2357352%3BO%26%2358856%3BC%26%2357353%3B%2B%26%2357352%3BOA%26%2357353%3B%2B%26%2357352%3BOB%26%2357353%3B%3D0%2C%E4%B8%94%26%2357352%3BO%26%2358856%3BC%26%2357353%3B%3D%CE%BBa%2C%E6%B1%82)
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将圆x2+y2+2x-2y=0按向量a=(1,-1)平移得到圆O(O为原点),直线l与圆O相交于A,B两点,若在圆O上存在点C,使OC+OA+OB=0,且OC=λa,求
将圆x2+y2+2x-2y=0按向量a=(1,-1)平移得到圆O(O为原点),直线l与圆O相交于A,B两点,若在圆O上存在点C,使OC+OA+OB=0,且OC=λa,求直线l的方程
OC=λaO
将圆x2+y2+2x-2y=0按向量a=(1,-1)平移得到圆O(O为原点),直线l与圆O相交于A,B两点,若在圆O上存在点C,使OC+OA+OB=0,且OC=λa,求
将圆标准化先:(x+1)^2+(y-1)^2=2,圆心(-1,1)按向量进行平移得:(0,0)即圆O为x^2+y^2=2
设直线l方程为y=kx+b,A、B坐标分别为(x1,y1)(x2,y2),根据OC+OA+OB=0,可得OAOB家教为120,则O到AB的弦心距为(根2/2),即|b|/根号(k^2+1)=(根2/2),OC=(λ,-λ)
http://zhidao.baidu.com/question/139666020.html?an=0&si=1
如图,⊙O方程,x²+y²=2.|a|=√2 C(1,-1)∈⊙O, L应该是OC相反半径的中垂线,方程我y=x+1(可保证OA+OB+OC=0,红色⊿)