作业帮求不定积分∫[x√(4-x²)]dx
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求不定积分∫[x√(4-x²)]dx
求不定积分∫[x√(4-x²)]dx
求不定积分∫[x√(4-x²)]dx
原式=1/2∫根号下(4-x^2)dx^2=1/2∫根号下(4-t)dt=-1/2*2/3*(4-t)^(3/2)+C=-1/3*(4-x^2)^(3/2)+C