在等腰直角三角形ABC与等腰直角三角形DBE中∠BDE=∠ACB=90°,且BE在AB边上,取AE的中点F,CD的中点G,连结GF(1)求FG与DC的位置关系
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/13 09:51:17
![在等腰直角三角形ABC与等腰直角三角形DBE中∠BDE=∠ACB=90°,且BE在AB边上,取AE的中点F,CD的中点G,连结GF(1)求FG与DC的位置关系](/uploads/image/z/3850268-68-8.jpg?t=%E5%9C%A8%E7%AD%89%E8%85%B0%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%8E%E7%AD%89%E8%85%B0%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2DBE%E4%B8%AD%E2%88%A0BDE%3D%E2%88%A0ACB%3D90%C2%B0%2C%E4%B8%94BE%E5%9C%A8AB%E8%BE%B9%E4%B8%8A%2C%E5%8F%96AE%E7%9A%84%E4%B8%AD%E7%82%B9F%2CCD%E7%9A%84%E4%B8%AD%E7%82%B9G%2C%E8%BF%9E%E7%BB%93GF%281%29%E6%B1%82FG%E4%B8%8EDC%E7%9A%84%E4%BD%8D%E7%BD%AE%E5%85%B3%E7%B3%BB)
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