(log2(3))^x-(log5(3))^x>=(log2(3))^(-y)-(log5(3))^(-y)
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(log2(3))^x-(log5(3))^x>=(log2(3))^(-y)-(log5(3))^(-y)
(log2(3))^x-(log5(3))^x>=(log2(3))^(-y)-(log5(3))^(-y)
(log2(3))^x-(log5(3))^x>=(log2(3))^(-y)-(log5(3))^(-y)
(log2(3))^x-(log5(3))^x>=(log2(3))^(-y)-(log5(3))^(-y)
求(log2)^3+(log5)^3+log5×log8的值.
log2(5) ×log5(8)=3步骤
求x的值 log4^x=-2/3 log2^(log5^x)=0log4^x=-2/3 log2^(log5^x)=0 分开的
若(log2(3))^x-(log5(3))^x>=(log2(3))^(-y)-(log5(3))^(-y) 则 A.x+y>0 B.x+y=0 D.
(log3^4+log5^2)(log2^9+log2^根号3)
(log5(10))^3-(log5(2))^3-3log5(10)*log2(5)
lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) )
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
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log2(log5 x)=-1
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一道高一数学题对数log2,详见补充已知log2[log1/2(log2^x)]=log3[log1/3(log3^y)]=log5[log1/5(log5^z)]=0,试比较x,y,z的大小?
求(log2)^3+(log5)^3+log5×log8的值.(以10为底)
2^(1/2log2 3)+(1/25)^log5 3=
log3 25×log2 27×log5 2^-3=_____