作业帮已知x(x-1)-(x²-y)=2,求代数式[（3x²+3y²）\2]-3xy
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已知x(x-1)-(x²-y)=2,求代数式[（3x²+3y²）\2]-3xy
已知x(x-1)-(x²-y)=2,求代数式[（3x²+3y²）\2]-3xy
已知x(x-1)-(x²-y)=2,求代数式[（3x²+3y²）\2]-3xy
x(x-1)-(x²-y)=2,
x²-x-x²+y=2
x-y=-2
x²+y²-2xy=4
x²+y²=2xy+4
[（3x²+3y²）\2]-3xy
=3(2xy+4)/2-3xy
=3xy+6-3xy
=6
x(x-1)-(x²-y)=2
x²-x-x²+y=2
x-y=-2
[（3x²+3y²）\2]-3xy
=(3x²-6xy+3y²)/2
=3(x-y)²/2
=6