函数y=sin(x+π/3)-sinx(x∈(0,π/2))的值域为a.-2,2 b,-1/2,√3/2 c.1/2,1 d.1/2,√3/2
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![函数y=sin(x+π/3)-sinx(x∈(0,π/2))的值域为a.-2,2 b,-1/2,√3/2 c.1/2,1 d.1/2,√3/2](/uploads/image/z/3856777-25-7.jpg?t=%E5%87%BD%E6%95%B0y%3Dsin%EF%BC%88x%2B%CF%80%EF%BC%8F3%EF%BC%89-sinx%28x%E2%88%88%280%2C%CF%80%EF%BC%8F2%29%29%E7%9A%84%E5%80%BC%E5%9F%9F%E4%B8%BAa.-2%2C2+b%2C-1%EF%BC%8F2%2C%E2%88%9A3%EF%BC%8F2+c.1%EF%BC%8F2%2C1+d.1%EF%BC%8F2%2C%E2%88%9A3%EF%BC%8F2)
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函数y=sin(x+π/3)-sinx(x∈(0,π/2))的值域为a.-2,2 b,-1/2,√3/2 c.1/2,1 d.1/2,√3/2
函数y=sin(x+π/3)-sinx(x∈(0,π/2))的值域为
a.-2,2 b,-1/2,√3/2 c.1/2,1 d.1/2,√3/2
函数y=sin(x+π/3)-sinx(x∈(0,π/2))的值域为a.-2,2 b,-1/2,√3/2 c.1/2,1 d.1/2,√3/2
sin(X+π/3)-sinx
=√3/2cosx-1/2sinx
=cos(x+π/6)
x∈(0,π/2)
则x+π/6∈(π/6,2π/3)
所以原式值域为(-1/2,√3/2 ),选B