已知函数f(x)=asinx*cosx-√3acos²x+√3/2a当x属于[0, π/2]时,f(x)的最小值是-√3,求在区间[-π,π]上,使函数f(s)取得最值时的所有自变量x的和
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![已知函数f(x)=asinx*cosx-√3acos²x+√3/2a当x属于[0, π/2]时,f(x)的最小值是-√3,求在区间[-π,π]上,使函数f(s)取得最值时的所有自变量x的和](/uploads/image/z/3860570-2-0.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dasinx%2Acosx-%E2%88%9A3acos%26sup2%3Bx%2B%E2%88%9A3%2F2a%E5%BD%93x%E5%B1%9E%E4%BA%8E%5B0%2C+%CF%80%2F2%5D%E6%97%B6%2Cf%EF%BC%88x%EF%BC%89%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E6%98%AF-%E2%88%9A3%2C%E6%B1%82%E5%9C%A8%E5%8C%BA%E9%97%B4%5B-%CF%80%2C%CF%80%5D%E4%B8%8A%2C%E4%BD%BF%E5%87%BD%E6%95%B0f%EF%BC%88s%EF%BC%89%E5%8F%96%E5%BE%97%E6%9C%80%E5%80%BC%E6%97%B6%E7%9A%84%E6%89%80%E6%9C%89%E8%87%AA%E5%8F%98%E9%87%8Fx%E7%9A%84%E5%92%8C)
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