分式的加减运算题一道.x/(x²+x)÷(x²+x-2)/x²-1+(x+1)/(x+2)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 10:53:41
分式的加减运算题一道.x/(x²+x)÷(x²+x-2)/x²-1+(x+1)/(x+2)
xRn@+((eÎ.v63c.1uP-V)HʂT)UBRE+EU~ *Hf{g7<ns\Gt罖Z"#%/N~`TRɂ`١[ථ%Z/Nєs/IJ}*pEJ[ x P 8l[FXk #vX՟Vc BDMra`}`u u & |D:Iöa`B`i뱐KQbТs mDiz`b1hE<Hbo)Aa,ltpjDoVH7\ rjY^Elo$W*Ss28x0dzlODrds0Iae}eKR ==/

分式的加减运算题一道.x/(x²+x)÷(x²+x-2)/x²-1+(x+1)/(x+2)
分式的加减运算题一道.
x/(x²+x)÷(x²+x-2)/x²-1+(x+1)/(x+2)

分式的加减运算题一道.x/(x²+x)÷(x²+x-2)/x²-1+(x+1)/(x+2)

由题意得:x/(x²+x)÷(x²+x-2)/(x²-1)+(x+1)/(x+2)
=x/x(x+1)× (x+1)(x-1)/(x-1)(x+2)+(x+1)(x+2)
=1/(x+2)+(x+1)/(x+2)
= (x+2)/(x+2)=1. 望采纳!

x/(x²+x)÷(x²+x-2)/x²=1/x+2
所以原式=1/(x+2)+(x+1)/(x+2)-1=0
求采纳