曲线M:y²=x与曲线N:(x-4)²+2y²=m²(m>0)相交于ABCD四个点,(1)求m的取值范围(2)求四边形ABCD面积的最大值及此时对角线AC与BD的交点坐标
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![曲线M:y²=x与曲线N:(x-4)²+2y²=m²(m>0)相交于ABCD四个点,(1)求m的取值范围(2)求四边形ABCD面积的最大值及此时对角线AC与BD的交点坐标](/uploads/image/z/3894869-29-9.jpg?t=%E6%9B%B2%E7%BA%BFM%EF%BC%9Ay%26%23178%3B%3Dx%E4%B8%8E%E6%9B%B2%E7%BA%BFN%EF%BC%9A%EF%BC%88x-4%29%26%23178%3B%2B2y%26%23178%3B%3Dm%26%23178%3B%28m%EF%BC%9E0%29%E7%9B%B8%E4%BA%A4%E4%BA%8EABCD%E5%9B%9B%E4%B8%AA%E7%82%B9%2C%EF%BC%881%EF%BC%89%E6%B1%82m%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%EF%BC%882%EF%BC%89%E6%B1%82%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E9%9D%A2%E7%A7%AF%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E5%8F%8A%E6%AD%A4%E6%97%B6%E5%AF%B9%E8%A7%92%E7%BA%BFAC%E4%B8%8EBD%E7%9A%84%E4%BA%A4%E7%82%B9%E5%9D%90%E6%A0%87)
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