已知xy+y²=3,x²+xy=-½,求2x²+3xy+y²的值
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已知xy+y²=3,x²+xy=-½,求2x²+3xy+y²的值
已知xy+y²=3,x²+xy=-½,求2x²+3xy+y²的值
已知xy+y²=3,x²+xy=-½,求2x²+3xy+y²的值
2x²+3xy+y²=(2x²+2xy)+(xy+y²)=2(x²+xy)+(xy+y²)=2*(-1/2)+3=2
只要把2x²+3xy+y²分解成题目中给的2(x²+xy)和(xy+y²)相加就可以了
L1已经给了正解了